Skip to main content

Repeated String HackerRank Solution | Java Solution | Programming Blog

Repeated String Solution in Java

Repeated String Solution in Java

Lilah has a string s of lowercase English letters that she repeated infinitely many times. Given an integer n, find and print the number of letter a in the first n letters of Lilah's infinite string.

For example, if the string s = "abcac" and n = 10, the substring we consider it "abcacabcac" the first 10 character of her infinite string. There are 4 occurrences of a in the substring.

So let's see solution of that.

import java.util.Scanner;

public class RepeatedString {

    public static void main(String[] args) {

        Scanner sc = new Scanner(System.in);

        System.out.println("Enter Number");
        int number = sc.nextInt();

        System.out.println("Enter String");
        String str = sc.next();
       
        int lengthOfstr = str.length();
       
        long occurenceOfA = 0;

        // Get all occurence of 'a' in given string
        for(int i=0; i< lengthOfstr;i++) {
            if(str.charAt(i)=='a') {
                occurenceOfA++;
            }
        }

        // Get repeated string length
        long totalOccurence = occurenceOfA * ( number/lengthOfstr);
        long remainingStr = number % lengthOfstr;

        // Loop through remaining string and count occurence
        // of 'a' character

        for(int i=0; i<remainingStr; i++) {

            char ch = str.charAt(i);
            if(ch == 'a')
                totalOccurence++;
            }

        System.out.println(totalOccurence);   

    }   

}

Output :-
Enter Number
10
Enter String
aba
7

Enter Number
100000000
Enter String
a
100000000


See other solution of HackerRank's Problem


Comments

Popular posts from this blog

Flipping the Matrix HackerRank Solution in Java with Explanation

Java Solution for Flipping the Matrix | Find Highest Sum of Upper-Left Quadrant of Matrix Problem Description : Sean invented a game involving a 2n * 2n matrix where each cell of the matrix contains an integer. He can reverse any of its rows or columns any number of times. The goal of the game is to maximize the sum of the elements in the n *n submatrix located in the upper-left quadrant of the matrix. Given the initial configurations for q matrices, help Sean reverse the rows and columns of each matrix in the best possible way so that the sum of the elements in the matrix's upper-left quadrant is maximal.  Input : matrix = [[1, 2], [3, 4]] Output : 4 Input : matrix = [[112, 42, 83, 119], [56, 125, 56, 49], [15, 78, 101, 43], [62, 98, 114, 108]] Output : 119 + 114 + 56 + 125 = 414 Full Problem Description : Flipping the Matrix Problem Description   Here we can find solution using following pattern, So simply we have to find Max of same number of box like (1,1,1,1). And last

Plus Minus HackerRank Solution in Java | Programming Blog

Java Solution for HackerRank Plus Minus Problem Given an array of integers, calculate the ratios of its elements that are positive , negative , and zero . Print the decimal value of each fraction on a new line with 6 places after the decimal. Example 1 : array = [1, 1, 0, -1, -1] There are N = 5 elements, two positive, two negative and one zero. Their ratios are 2/5 = 0.400000, 2/5 = 0.400000 and 1/5 = 0.200000. Results are printed as:  0.400000 0.400000 0.200000 proportion of positive values proportion of negative values proportion of zeros Example 2 : array = [-4, 3, -9, 0, 4, 1]  There are 3 positive numbers, 2 negative numbers, and 1 zero in array. Following is answer : 3/6 = 0.500000 2/6 = 0.333333 1/6 = 0.166667 Lets see solution Solution 1 import java.io.*; import java.math.*; import java.security.*; import java.text.*; import java.util.*; import java.util.concurrent.*; import java.util.function.*; import java.util.regex.*; import java.util.stream.*; import static java.util.st